3k^2-14k+4=3k

Solution for 3k^2-14k+4=3k equation:

3k^2-14k+4=3k

We move all terms to the left:

3k^2-14k+4-(3k)=0

We add all the numbers together, and all the variables

3k^2-17k+4=0

a = 3; b = -17; c = +4;
Δ = b2-4ac
Δ = -172-4·3·4
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{241}}{2*3}=\frac{17-\sqrt{241}}{6}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{241}}{2*3}=\frac{17+\sqrt{241}}{6}
$